You are looking at opening a savings account and have seen that ANZ Bank seems to be offering a good rate on one of their accounts. The account would pay interest monthly. You work out that if you put $1000 in this account, you would have $1012.07 in your account at the end of the year. What would the advertised rate on this account be?
| a. | 1% p.a. compounding monthly | |
| b. | 1.2004% p.a. compounding monthly | |
| c. | 1.207% p.a. | |
| d. | 0.1% per month | |
| e. | None of them. |
To determine the advertised interest rate on the savings account offered by ANZ Bank, we can use the formula for compound interest:
�=�(1+��)��
Where:
� is the future amount of money in the account.
� is the initial principal amount ($1000 in this case).
� is the annual interest rate (the rate we want to find).
� is the number of times the interest is compounded per year (monthly, in this case).
� is the number of years (1 year in this case).
We are given that after 1 year, the account balance will be $1012.07.
Plugging in the values:
1012.07=1000(1+�12)12⋅1
Now, we need to solve for �.
Let’s simplify the equation step by step:
Divide both sides by 1000:
1012.071000=(1+�12)12
Now, take the 12th root of both sides:
(1012.071000)112=1+�12
Subtract 1 from both sides:
(1012.071000)112−1=�12
Now, multiply both sides by 12 to isolate �:
�=12((1012.071000)112−1)
Now, calculate the value within the parentheses:
(1012.071000)112−1≈0.012004
Now, multiply by 12:
�≈12⋅0.012004≈0.14405
So, the annual interest rate (�) is approximately 0.14405 or 14.405%.
Now, let’s check the options provided:
a. 1% p.a. compounding monthly – This is too low. b. 1.2004% p.a. compounding monthly – This matches our calculated rate (approximately 1.2004%). c. 1.207% p.a. – Close but not exactly the same as our calculated rate. d. 0.1% per month – This is much higher than our calculated rate. e. None of them – This is not correct since option (b) matches our calculated rate.
So, the correct answer is option (b): 1.2004% p.a. compounding monthly.
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